Question

Leyla is redecorating her living room. The room is in the shape of a right rectangular prism. The dimensions of the room are 15 feet in length by 10 feet in width by 8 feet in height.

She plans to cover the floor with hardwood. The cost of the hardwood is $3 per square foot. She plans to cover the walls and the ceiling with paint. Each container of paint costs $30 and can cover 275 ft².
What is the total cost of the hardwood flooring and paint needed for this room?


Drag and drop the responses to correctly complete these sentences.

Answer 1

$510

Explanation:

The floor of the room measures 15 ft in length and 10 ft in width.

The area of the floor is length × width = 15 ft × 10 ft = 150 ft².

The hardwood costs $3/ft².

The cost of the hardwood is: $3/ft² × 150 ft² = $450

The area of the walls is the lateral surface area of the rectangular prism.

The lateral surface area of the rectangular prism is the perimeter of the base times the height.

perimeter of the base = 15 ft + 15 ft + 10 ft + 10 ft = 50 ft

height = 8 ft

lateral area = total area of the walls = perimeter × height = 50 ft × 8 ft = 400 ft²

The paint costs $30/(275 ft²).

She needs to paint 400 ft².

400 ft² / 275 ft² = 1.45

She needs 1.45 containers of paint, but she must buy full containers of paint, so she must buy 2 containers since 1 container is not enough.

Cost of paint: 2 × $30 = 60

Total cost of hardwood and paint = $450 + $60 = $510

Answer 2

Total floor: 150 sq ft = $450

Wall and Ceiling: 550 sq ft = $60

Total cost $510

Explanation:

Floor: 15 sq ft * 10 sq ft (L * W) = 150 sq ft

150 sq ft * $3 = $450

Walls: 2(H * L) = 2(8*15) = 240 sq ft

2(H * W) = 2(8*10) = 160

Total walls sq ft = 400 sq ft

Ceiling is same as floor = 150 sq ft

Total sq ft painted = 550 sq ft

550 sq ft / 275 sq ft (covered per paint) = 2 paints = $60

$450 floor + $60 paint = $ 510