Question

a tennis ball is launched from the floor at a velocity of 90 m/a at an angle of 13 degrees to the horizontal. calculate its range

Answer 1

~186

Step-by-step explanation:

1) R= (V^2 × sin A ) /g

V=90 m/a

A= 13°

g= 9.8 or 10 (I will take 9.8 for right result)

R= (90^2 × sin 13) / 9.8 = 185.928932672 ~ 186