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Please help 50 points: A ball is thrown straight up, from 3 m above the ground, with a velocity of 14m/s. When does it hit the ground? Use vertical motion formula.

User Uolot
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2 Answers

12 votes
12 votes

Explanation:

In this question, to find the total height first, we must also take into consideration the acceleration due to gravity as well. To find the distance by which acceleration due to gravity pulls the ball down must know the Initial velocity.

In the answer key, it says that gravity changes the ball's height by a distance of -5t^2

Is initial velocity in this question 0 or 14m/s? Because if it is 14, then gravity should change the balls position by -(14+5t^2), not -5t^2, because if I remember correctly, the formula for finding distance is vt(initial velocity)+(1/2)at^2 ,and not just (1/2)at^2

User Mcastle
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2.8k points
14 votes
14 votes

Answer:

3.058s

Explanation:

i cant rewrite everything i solve in the paper sorry

User Vincent Hiribarren
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2.8k points