Question

What is the molarity of a solution that contains 114.4g NaCl (molar mass= 58.44 g/mol) in 1.2 L solution?

Answer 1

1.6 M.

Step-by-step explanation:

We want to find the molarity of a solution that contains 114.4 g NaCl in a 1.2 L solution.

Recall that molarity is given by:

`\displaystyle \text{M} = \frac{\text{ mols solute}}{\text{ L soln.}}`

Convert 114.4 g NaCl to mol NaCl using its molecular weight:

`\displaystyle 114.4 \text{ g NaCl} \cdot \frac{1 \text{ mol NaCl}}{58.44 \text{ g NaCl}} = 1.958\text{ mol NaCl}`

Therefore, the molarity of the solution will be:

`\displaystyle \text{M} = \frac{1.958 \text{ mol NaCl}}{1.2\text{ L soln.}} = 1.6 \text{ M}`

In conclusion, the molarity of the solution is 1.6 M.