Question

Calculate the percentage of sulphur in MgSO4.2H₂O​

Answer 1

20.51%

Step-by-step explanation:

Mass of S = 32g

Mass of MgSO₄ x 2H₂O = 24 + 32 + 64 + 36 = 56 + 100 = 156

• %S = 32/156

• %S = 8/39
• %S = 20.51%

Answer 2

`Molecular \: mass \: of \: MgSO_(4).2H_(2)O\:, \\ \\ ⇝ 24 + 32 + 16 * 4 + 2(2 * 1 + 46) \\ \\ ⇝ 24 + 32 + 64 + 36 \\ \\ ⇝156 \: u`

`\bold\pink{Percentage \: of \: substance \: in \: compound} \\ \\ \bold\pink{⇝ (mass \: of \: substance)/(mass \: of \: compound) * 100}`

`\% \: age \: of \: Sulphur \: (S) = (32)/(156) * 100 \\ \\ ⇝0.205 * 100 \\ \\ \fbox\blue{\:⇝ 20.5\%\:}`

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