Question

How much heat must you remove from the 2.00 kg of 41.3 C tea to lower its temperature to 0.0 C?

Answer 1

• Mass=m=2kg
• Initial temperature=41.3°C
• Specific heat capacity=4184J/kgK
• Final temperature=0°C

Using thermodynamics

`\\ \sf\longmapsto Q=mc\Delta T`

`\\ \sf\longmapsto Q=2(4184)(0-41.3)`

`\\ \sf\longmapsto Q=8368(-41.3)`

`\\ \sf\longmapsto Q=345598.4J`