Question

what is the slope-intercept form of the equation of the line that contains the points (-3,-3) and (4,5)

Answer 1

`y=1.14x+0.420`

Explanation:

Given the following question:

Point A = (-3,-3) = (x1, y1)
Point B = (4, 5) = (x2, y2)

To write the points in slope intercept form we must first calculate the slope using rise over run. Once we have the slope, we substitute the values into the formula for slope intercept which is y = mx + b and then solve for b to have our answer.


`m=(y2-y1)/(x2-x1)`

`m=(5--3)/(4--3) =(8)/(7)`

`8/7=1.14`

`m=1.14`

Now that we have the slope substitute the values:

`y=mx+b`

`y=-3`

`m=1.14`

`x=-3`

`-3=1.14(-3)+b`

`1.14*-3=-3.42`

`-3=-3.42+b`

`-3.42+3.42=0`

`-3+3.42=0.42`

`0.42=b`

`b=0.42`

`y=1.14x+0.420`

Your answer is "y = 1.14x + 0.420."

Hope this helps.