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Distance between the lines 3x +4y =9 and 6x + 8y =15 is

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Answer:

  • 0.3 units

Explanation:

Given lines in standard form:

  • ax + by = c
  • 3x +4y =9 and
  • 6x + 8y =15

We can see they have same slopes:

  • m = -3/4 and
  • m = -6/8 = -3/4

The lines after simplification of the second one:

  • 3x + 4y = 9
  • 3x + 4y = 7.5

Since the lines are parallel, use the distance formula:


  • d= |c_1-c_2|/√(a^2+b^2)

Substitute the values and find d:


  • d = |9-7.5|/√(3^2+4^2) = |1.5|/√(25) =1.5/5=0.3
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