Question

Find the equation of the circle in standard form given the center, point or radius. Show your solution.

Center (-3,5) & Point (-2,1)​

Answer 1

(x + 3)^2 + (y - 5)^2 = 17

Explanation:

To find the radius: distance from point (-2,1) to the center from point (-3,5).

d = sqrt [(-2 - -3)^2 + (1 -5)^2]

d = sqrt [(-2 + 3)^2 + (1 -5)^2]

d = sqrt (1)^2 + (-4)^2 = sqrt 17

Radius = sqrt 17

Equation of the circle:

(x - h)^2 + (y - k)^2 = r^2

h = 3, k = 5, r = sqrt 17

(x - -3)^2 + (y - 5)^2 = (sqrt 17)^2

(x + 3)^2 + (y - 5)^2 = 17