Answer:
1
![(99)/(100)](https://img.qammunity.org/2022/formulas/mathematics/high-school/9cb6c54zup135bahhfqsdksem3li7ocep3.png)
Explanation:
I would start by turning the parentheses fractions into one fraction.
You could do binomial multiplication and get
but it might take longer.
So I would just turn them into one fraction by finding the common denominator.
The common denominator here is 10
![(1)/(5) ((2)/(2) )=(2)/(10)](https://img.qammunity.org/2022/formulas/mathematics/high-school/muhm3zm6fob8susogb2ejk67l789vq95bb.png)
![(1)/(2) ((5)/(5) )=(5)/(10)](https://img.qammunity.org/2022/formulas/mathematics/high-school/qr1yua8vq6978n96mda18p18haa51qu9xl.png)
Now add
![(2)/(10) +(5)/(10) =(7)/(10)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ruuyb3520gj56p7fw7mrg7syrflr6uffzv.png)
Now apply:
![((a)/(b) )^(2) =(a^(2) )/(b^(2) )](https://img.qammunity.org/2022/formulas/mathematics/high-school/q1rmamn1zslefnr07q306jljqck5tm0ol1.png)
![((7)/(10) )^(2) =(7^(2) )/(10^(2) ) =(49)/(100)](https://img.qammunity.org/2022/formulas/mathematics/high-school/f4w7szanb8b7atpvvu9uoentrowjc0dby8.png)
Now, multiplying the other fraction we get
![(3)/(10) (5)=(15)/(10)](https://img.qammunity.org/2022/formulas/mathematics/high-school/7klfnxct152uv7nfe7hp1tnopk1423tp74.png)
Now turn this into a fraction with denominator 100 to add the two fractions
![(15)/(10) ((10)/(10) )=(150)/(100)](https://img.qammunity.org/2022/formulas/mathematics/high-school/kan54humkoee3nsd35u7k2e58xh7cmjltf.png)
![(49)/(100) +(150)/(100) =(199)/(100) =1(99)/(100)](https://img.qammunity.org/2022/formulas/mathematics/high-school/e197euj4w2mb6s37s559eluzk9o2of2kfl.png)
There is also another method to add or subtract fractions without multiplying to get a common denominator in case you are interested:
±
=
![(ad+bc)/(bd)](https://img.qammunity.org/2022/formulas/mathematics/high-school/95rbcsomlzcmwmh4d0jdeebbrm82s01rg5.png)