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Consider the reaction. 2Pb(s)+O2(g)⟶2PbO(s) An excess of oxygen reacts with 451.4 g of lead, forming 386.5 g of lead(II) oxide. Calculate the percent yield of the reaction.
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Consider the reaction.

2Pb(s)+O2(g)⟶2PbO(s)

An excess of oxygen reacts with 451.4 g of lead, forming 386.5 g of lead(II) oxide. Calculate the percent yield of the reaction.

User Kangjianwei
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1 Answer

7 votes

Answer:837.9

Explanation:add those 2 numbers

User NiklasPor
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5.4k points
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