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Write the equation of a line in point slope form that is PERPENDICULAR to y = - 1/3 * x + 5 and passes through the point (6, 4)

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Answer:


if \: \: l_1 \perp\: l_2 \rightarrow \: m_1 * (1)/(m_2) = - 1\\ \therefore \: m_1 = - m_2 = (1)/(3) \\ y = mx + c \\ 4 = (1)/(3)(6) + c \\ c = 4 - 2\\ c = 2 \\ \therefore y = (1)/(3)x + 2

User Philipp Zedler
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