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What is equation represents a line which is perpendicular to the line 4x-3y=12

User Vhbazan
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1 Answer

5 votes

Answer:

y = (-3/4)x + b

Explanation:

If the slope of a given line is m, then the slope of any line perpendicular to the given line is the negative reciprocal of m: -1/m.

First we need to calculate the slope of the given line, 4x - 3y = 12. Dividing all three terms by -3, we get

y = (4/3)x - 4

and note that the slope of this line is 4/3. Then the slope of any line perpendicular to this line is -3/4.

Then a general formula for a line perpendicular to 4x - 3y = 12 is

y = (-3/4)x + b, where the value of b depends upon the point on the given line through which the perpendicular ilne passes.

User Liat
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