71.3k views
3 votes
What is equation represents a line which is perpendicular to the line 4x-3y=12

User Vhbazan
by
7.6k points

1 Answer

5 votes

Answer:

y = (-3/4)x + b

Explanation:

If the slope of a given line is m, then the slope of any line perpendicular to the given line is the negative reciprocal of m: -1/m.

First we need to calculate the slope of the given line, 4x - 3y = 12. Dividing all three terms by -3, we get

y = (4/3)x - 4

and note that the slope of this line is 4/3. Then the slope of any line perpendicular to this line is -3/4.

Then a general formula for a line perpendicular to 4x - 3y = 12 is

y = (-3/4)x + b, where the value of b depends upon the point on the given line through which the perpendicular ilne passes.

User Liat
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.