Answer:
r = ∛(V/π)
Explanation:
In algebra, when dealing with equations, we are usually given a variable with some constants and are asked to solve for said variable. Here are some examples of typical equations you'd see in algrebra:
x + 1 = 2
2(x - 2) = 6
(x - 3)(x + 5) = 0
But what happens if most, if not all, of the terms in an equation are variables? These equations are known as literal equations. They can be random variable equations or formulas you'd see on a formula sheet (like the Pythagorean Theorem, for example). Here are some examples of literal equations:
vw + xy = z
A = 1/2(bh)
a^2 + b^2 = c^2
In the question here, we are given an equation V = πr^3 and are asked to solve for r. Just like any equation, you'd solve for the variable by doing the order of operations (grouping, exponents, multiplication or addition, and addition or subtration) backwards.
V = πr^3
First, we divide π on both sides to isolate r^3.
V/π = r^3
Then, we take the square root of both sides to isolate r.
∛(V/π) = r
r = ∛(V/π)
(And in case you needed to solve for r for v=(4/3)πr^3, r = ∛(3V/4π).)