Question

A box contains 8 red, 6 yellow, and 7 blue marbles. A marble is drawn, not replaced, and a second marble is

drawn. What is the probability of selecting 2 yellow marbles?

Answer 1

Probability=

(number if outcomes favourable)/(total number of outcomes)

Therefore P(no red/green)=1-(8/21+6/21)

=1-(8+6)/21=1-14/21=(21×1-14)/21=(21-14)/21

=7/21=1/3 ans

Explanation: