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What is the concentration in g/dm3 of a solution of potassium manganate where 5g of potassium manganate is dissolved in 2 dm3 of water?

Please help!!!

User JoelFan
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1 Answer

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Answer: 2.5 g/dm^3

Explanation: potassium manganate, KMnO4, has a molar mass of 197.1 g/mole. 5 g KMnO4 would be (5g/(197.1 g/mole) = 0.0254 moles K2MnO4.

Calculating moles was a waste of my time, becuse the answer requested is in 6/dm^3. But I'll leave it as a lesson to "always read the full question before answering." [Spoiler alert: I rarely do, and often waste my time].

We add 5g to 2 dm^3 of water. 5g/2dm^3 = 2.5 g/dm^3.

User Vadim Eksler
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