Question

Nd the value of h(b) = 3b^2 -2b + 1 when b = -5 *

3 points
21
216
-84
66

Answer 1

Given :-

• h(b) = 3b² - 2b + 1

To find :-

• The value of h(b) when b = -5 .

Answer :-

We have ,

• h(b) = 3b² - 2b + 1

When b = -5 ,

• h(-5) = 3*(-5)² -2*(-5) + 1
• h(-5) = 3*25 +10 + 1
• h(-5) = 75 + 11
• h(-5) = 86

Answer 2

`▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪`

For b = - 5, the given expression will be equal to :

• 
  `3 {b}^(2) - 2b + 1`

• 
  `3( - 5) {}^(2) - 2( - 5) + 1`

• 
  `(3 * 25) + 10 + 1`

• 
  `75 + 11`

• 
  `86`