Question

Find the distance between the pair of points.
​(19​,−8​) and ​(−14​,−23​)

Answer 1

Answer:36.25

Step-by-step explanation:distance between (x1, y1) and (x2,y2) is square root of (x2-x1)^2 + (y2-y1)^2. think of graph the distance between two points is the hypotenuse of a right angle triangle where the height is the difference of y and base is the difference of x

= square root of (19+14)^2 +(-23+8)^2= 36.25

Answer 2

36.25 units

Explanation:

Hi there!

`d=√((x_2-x_1)^2+(y_2-y_1)^2)` where two endpoints are
`(x_1,y_1)` and
`(x_2,y_2)`

Plug in the given points ​(19​,−8​) and ​(−14​,−23​):

`d=√((19-(-14))^2+(-8-(-23))^2)\\d=√((19+14)^2+(-8+23)^2)\\d=√((33)^2+(15)^2)\\d=√(1089+225)\\d=√(1314)\\d=36.25`

Therefore, the distance between the points is approximately 36.25 units.

I hope this helps!