Question

6. 0.465 mole sample of gas exerts 4.43 atm of pressure in a 2.25 L container. What is the temperature of the gas in the container?

Answer 1

T = 262K

Step-by-step explanation:

n = 0.465

P = 4.43 atm

V = 2.25 L

T = ?

Follow this equation below

PV = nRT

4.43 x 2.25 = 0.465 x 0.08206 x T

9.97 = 0.038 x T

(Dividing both sides by 0.038 to get rid of it)

T = 262K or you could say 262.4K

Hope this helps!!