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If e^f(x)=1+x^2, then f(x)=

User Hanno
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2 Answers

3 votes

Explanation:

point dene ke liye sukriya tumhara dost

User Hkariti
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6 votes

Answer:


\displaystyle f(x) = \ln\left( 1 + x^2\right)

Explanation:

We are given that:


\displaystyle e^(f(x)) = 1 + x^2

And we want to find f(x).

We can take the natural log of both sides:


\displaystyle \ln\left(e^(f(x))\right) = \ln\left( 1 + x^2\right)

Recall that ln(aᵇ) = bln(a). Hence:


\displaystyle f(x) \ln(e) = \ln\left ( 1 + x^2\right)

By definition ln(e) = 1. Therefore:


\displaystyle f(x) = \ln\left( 1 + x^2\right)

User Manisha  Bano
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