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Electric field

what is the magnitude of the electric field from 30 cm from a point charge of q = 30 NC?

User Pradeepa
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1 Answer

10 votes

Step-by-step explanation:

Electric field = k q/r²

= 9×10⁹×30/(30×10^-2)²

= 3×10¹² N/C

User Seneca
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