Question

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Answer 1

15.
`\displaystyle 32`

14.
`\displaystyle a^(5n)`

13.
`\displaystyle (12a^4)/(b^3)`

12.
`\displaystyle 9x^2`

11.
`\displaystyle (9)/(ab)`

Step-by-step explanations:

15.
`\displaystyle (1)/(32)^(-1) = (1)/(2)^(-5) \\ \\ \boxed{32} = (1)/(32)^(-1)`

14.
`\displaystyle \boxed{a^(5n)} = (1)/(a^(-5n))`

13.
`\displaystyle \boxed{(12a^4)/(b^3)} = (12b^(-3))/(a^(-4))`

12.
`\displaystyle \boxed{9x^2} = (9)/(-x^2)`

11.
`\displaystyle \boxed{(9)/(ab)} = (ab)/(9)^(-1)`

For exercises twelve to fourteen, accourding to the six exponential rules, in this case, if there is a negative in either the denominatour or numeratour, you bring it to the bottom or top and it becomes positive.

For exercise fifteen, multiply the fraction five times, then take the multiplicative inverce of it [negative exponent].

For exercise eleven, you simply take the multiplicative inverce of the fraction provided.

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