Question

What is an equation of the line that passes through th (3,-1) and has a slope of 2?​

Answer 1

The given point to us is (3,-1) and the slope of the line is 2 . We can use the point slope form of the line as ,

`\sf\longrightarrow m ( x - x_1) = y - y_1`

Substitute the values ,

`\sf\longrightarrow 2( x - 3 ) = y - (-1)`

Simplify LHS and RHS ,

`\sf\longrightarrow 2x - 6 = y +1`

Put all terms on one side ,

`\sf\longrightarrow \boxed{\bf 2x - y -7=0}`