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Answer:
0.15 dL
Explanation:
The volume of the bar is ...
V = LWH
V = (5 cm)(3 cm)(1 cm) = 15 cm³
1 dL = 100 cm³, so this volume is ...
(15 cm³)(1 dL)/(100 cm³) = 0.15 dL
The bar will displace 0.15 deciliters.
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