Question

4. At what temperature will 1.21 mol of oxygen (O2), exert a pressure of 1862 mmHg in a

5.12 L cylinder?

Answer 1

Pressure = 1820 mmHg ... T = ( 2.39atm x 5.12L ) / ( 0.4041 moles x 0.08206atm. ... n is moles, R is the gas constant, and T is temperature in Kelvins.

Step-by-step explanation:

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