Question

. 1
Find f
for the function f.
f(x) = 3x² + 3, x > 0
And find the domain

Answer 1

y =
`\sqrt{(x-3)/(3) }`

Domain = [3, infinity)

Explanation:

x = 3y^2 + 3

3y^2 = x - 3

y^2 = (x-3)/3

y =
`\sqrt{(x-3)/(3) }`