Question

What is the value of the axis of symmetry?
y = 3x² + x

Answer 1

`x=-(1)/(6)`

Explanation:

For a quadratic function in standard form
`y=ax^2 + bx + c`, the axis of symmetry can be expressed as
`x=(-b)/(2a)`

For the equation
`y=3x^2+x`

`a=3, b=1, c=0`

Therefore, the axis of symmetry is
`x=-(1)/(6)`