Question

60 points! please help me i would greatly appreciate it!

Answer 1

`\huge\boxed{\sf 186.59\ L}`

Step-by-step explanation:

Given that:

No. of moles = 8.33 mol

At STP, 1 mol. of all gases has a molar value of 22.4 dm³/mol

So,

Volume of 8.33 mol of N₂ gas:

= no. of moles x molar value

= 8.33 x 22.4

= 186.59 dm³

Since 1 dm³ = 1 L

So,

Volume = 186.59 L

`\rule[225]{225}{2}`