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what is the specific heat of a substance if 60.0 j are required to increase the temperature of 6 grams by 11 degrees celsius?
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what is the specific heat of a substance if 60.0 j are required to increase the temperature of 6 grams by 11 degrees celsius?

User Shalonda
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1 Answer

4 votes

Answer:

Using the specific heat capacity formula:

q = mc ∆ t

60.0 J = (6g)(x)(11*C)

x = 0.9 J/g*C

Aluminum

User John Ruiz
by
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