Question

And subtracting polynomials

Geometry:
Explain the steps in paragraphs to find the measure of the
missing side (AC) of the triangle shown below.


please help me i have more work to do in my other classes that i wont have time to do this one today :(

Answer 1

• 10 cm

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Explanation :

• This is Right Angled Triangle.

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Solution :

• We'll solve this using the Pythagorean Theorem.

where,

• AB (8 cm) is the perpendicular
• BC (6 cm) is the Base.
• AC is the Hypotenuse.

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We know that,

`{\longrightarrow \bf \qquad (AC) {}^(2) = (AB) {}^(2) +( BC) {}^(2) }</p><p>`

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Now, we will substitute the given values in the formula :

`{\longrightarrow \sf \qquad (AC) {}^(2) = (8) {}^(2) +( 6) {}^(2) }`

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We know that, (8)² = 64 and (6)² = 36. So,

`{\longrightarrow \sf \qquad (AC) {}^(2) = 64 + 36 }`

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Now, adding 64 and 36 we get :

`{\longrightarrow \sf \qquad (AC) {}^(2) = 100 }`

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Now, we'll take the square root of both sides to remove the square from AC :

`{\longrightarrow \sf \qquad \sqrt{(AC) {}^(2)} = √(100) }`

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• When we take the square root of (AC)² , it becomes AC

`{\longrightarrow \sf \qquad AC = √(100) }`

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We know that, square root of 100 is 10 .

`{\longrightarrow \bf \qquad AC = 10 }`

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So,

• The measure of the missing side AC is 10 cm .