Question

a 1.50*10^-5 C charge feels a 2.89*10^-3 N force when it moves 288m/s perpendicular (90) deg to a magnetic field. how strong is the field?

Answer 1

The strength of the magnetic field is approximately 7.59*10^-5 T.

Step-by-step explanation:

To find the strength of the magnetic field, we can use the formula F = qvBsinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field. In this case, the charge is 1.50*10^-5 C, the force is 2.89*10^-3 N, the velocity is 288 m/s, and the angle is 90 degrees.

Plugging these values into the formula, we get 2.89*10^-3 N = (1.50*10^-5 C)(288 m/s)(B)(1). Solving for B, we find that the strength of the magnetic field is approximately 7.59*10^-5 T.