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Sin A + cos A/ sin A - cos A +sin A - cos A /sin A + cos A =​
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Sin A + cos A/ sin A - cos A +sin A - cos A /sin A + cos A =​

User Duran
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1 Answer

1 vote

Answer:

Explanation:


(sinA+cosA)/(sinA-cosA) +(sinA-cosA)/(sinA+cosA) \\=((sinA+cosA)^2+(sinA-cosA)^2)/((sinA+cosA)(sinA-cosA)) \\=(sin^2A+cos^2A+2sinAcosA+sin^2A+cos^2A-2sinAcosA)/(sin^2A-cos^2A) \\=(1+1)/(-(cos^2A-sin^2A)) \\=(2)/(-cos2A) \\=-2sec(2A)

User TheLearner
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