Sin A + cos A/ sin A - cos A +sin A - cos A /sin A + cos A =

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asked Dec 5, 2022 9.8k views

3 votes

Sin A + cos A/ sin A - cos A +sin A - cos A /sin A + cos A =

Mathematics
college

Duran asked

by Duran

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Answer:

Explanation:

$(sinA+cosA)/(sinA-cosA) +(sinA-cosA)/(sinA+cosA) \\=((sinA+cosA)^2+(sinA-cosA)^2)/((sinA+cosA)(sinA-cosA)) \\=(sin^2A+cos^2A+2sinAcosA+sin^2A+cos^2A-2sinAcosA)/(sin^2A-cos^2A) \\=(1+1)/(-(cos^2A-sin^2A)) \\=(2)/(-cos2A) \\=-2sec(2A)$

TheLearner answered Dec 9, 2022

by TheLearner

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