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In a right triangle if sin θ = 3/8, find sec θ

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Answer:

Explanation:

sin θ = 3/8

sin²θ = (3/8)²

1 - cos²θ = 9/64

cos²θ = 1 - (9/64)

cos²θ = 55/64

cosθ = √55/8

secθ = 8/√55

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