Answer:
y = 4
Explanation:
Using the slope, m = 5, and the given point, (1, -6), plug in these values into the point-slope formula:
y - y1 = m(x - x1)
y - (-6) = 5(x - 1)
y + 6 = 5x - 5
Subtract 6 on both sides of the equation to isolate y:
y + 6 - 6 = 5x - 5 - 6
y= 5x - 11
Therefore, the linear equation in slope-intercept form is y = 5x - 11.
To find the value of the y-coordinate in point (3, y ):
Plug in the value of x = 3 into the equation, y = 5x - 11
y= 5x - 11
y= 5(3) - 11
y = 15 - 11
y = 4
Therefore, the value of the y-coordinate in point (3, y) is 4.