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Express the following complex numbers 6+2i divided by 2+4i in the form of a+ib

1 Answer

2 votes

Answer:

Multiplying both numerator and denominator by the Complex conjugate of the denominator

Therefore,

(3+4i)

(2−3i)

=

3+4i

2−3i

×

3−4i

3−4i

=

(3)

2

−(4i)

2

(2−3i)(3−4i)

=

9+16

(6+12i

2

)−(9+8)i

=

25

−6−17i

=

25

−6

+

25

−17

i

Here, A=

25

−6

and B=

25

−17

Explanation:

User Alex Haas
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