Answer:
Explanation:
Place the numbers representing the divisor and the dividend into a division-like configuration.
−5
1
−5
2
−10
0
The first number in the dividend (1)
is put into the first position of the result area (below the horizontal line).
−5
1
−5
2
−10
0
1
Multiply the newest entry in the result (1)
by the divisor (−5) and place the result of (−5) under the next term in the dividend (−5)
.
−5
1
−5
2
−10
0
−5
1
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
−5
1
−5
2
−10
0
−5
1
−10
Multiply the newest entry in the result (−10)
by the divisor (−5) and place the result of (50) under the next term in the dividend (2)
.
−5
1
−5
2
−10
0
−5
50
1
−10
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
−5
1
−5
2
−10
0
−5
50
1
−10
52
Multiply the newest entry in the result (52)
by the divisor (−5) and place the result of (−260) under the next term in the dividend (−10)
.
−5
1
−5
2
−10
0
−5
50
−260
1
−10
52
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
−5
1
−5
2
−10
0
−5
50
−260
1
−10
52
−270
Multiply the newest entry in the result (−270)
by the divisor (−5) and place the result of (1350) under the next term in the dividend (0)
.
−5
1
−5
2
−10
0
−5
50
−260
1350
1
−10
52
−270
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
−5
1
−5
2
−10
0
−5
50
−260
1350
1
−10
52
−270
1350
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
1x3+−10x2+(52)x−270+1350x+5
Simplify the quotient polynomial.
x3−10x2+52x−270+1350x+5