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X^{2} =(2x-1)^{2} please hep me

User Ckarbass
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Answer:


{x}^(2) = {(2x - 1)}^(2) \\ {x}^(2) = 4 {x}^(2) - 4x + 1 \\ 3 {x}^(2) - 4x + 1 = 0 \\ (x - 1)(x - (1)/(3) ) = 0 \\ \therefore \: x = 1 \: or \: x = (1)/(3)

User JVGD
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