HELP O_O Use the remainder theorem to find the remainder when p(x)=x^4-9x^3-5x^2-3x+4 is divided by x+5 A.) 1644 B.) 1244 C.) -636 D.) -644

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asked Jun 15, 2023 87.6k views

2 Answers

Pinser · Answer 1 · 2023-06-16T08:56:49+0000

Use the remainder theorem to find the remainder when p(x)=x^4-9x^3-5x^2-3x+4 is divided by x+5

B.) 1244

C.) -636

D.) -644

~~~~~~~~~~~~~~~~~~~~~

$\sf p(x)=x^4-9x^3-5x^2-3x+4$

$\sf p(x) = (-5)^4 - 9(-5)^3 (-5)^2 - 3 (-5) + 4$

$\sf \green {(p(x) = 1644)}$

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Balaji Ambresh · Answer 2 · 2023-06-19T17:45:08+0000

Answer:

A.) 1644

given equation:
$\sf p(x)=x^4-9x^3-5x^2-3x+4$

To be divided with ( x + 5 )

Then,

x + 5 = 0

x = -5

Put this into the equation to find the remainder.

$\sf p(x)=(-5)^4-9(-5)^3-5(-5)^2-3(-5)+4$

$\sf p(x)= 1644$