Question

Find the equation of the line that passes through the points (4, -2) and (3, -1).

Answer 1

y = -x + 2

Explanation:

linear equation is y = mx + b, where m is the slope

m = (y2 -y1)/(x2-x1) => (-1+2/(3-4 )

m = 1/-1 => -1

Now let's use given point (4, -2) and m value, so we can solve for b.

-2 = (-1)(4) + b => b= -2+4 => b= 2

Therefore, our equation is now y = -x + 2