Question

11. Ms. Mullins attaches herself to a strong bungee cord and jumps off a bridge. At time t = 3 sec, the cord

first becomes taut. From that time on, Mullins' distance, d feet, from the water below the bridge is given by the
following equation: d = -80(sin[1.2(t -3))+90. d=-80lsin [ 1.2]) +90

Answer 1

soory to say your question i think wrong