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What is root-16 + root49 written as a complex number in the form a+bi?

User Nedzad G
by
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1 Answer

6 votes

Answer:


→√( - 16) + √(49)

  • We know that, i = √-1
  • Form → a + ib


→( √( - 1) * √(16) ) + ( √(49) )\\=i √(16)+√(49) \\ = 4i + 7 \\ = \boxed{7 + 4i}✓

  • (7 + 4i) is the right answer.
User Deepak Kumar
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