Question

A line has a slope of 110 and passes through the point (5,10). What is its equation in point-slope form? Use the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions

Answer 1

y - 10 = 110 ( x - 5)

explanation :

i)

`\sf point \ slope \ form : \bold{y-y_(1)=m\left(x-x_(1)\right)}`

• y - 10 = 110 ( x - 5)

ii)

• y = 110x -540

• 10 = 110(5) - 540

• 10 = 550 - 540

• 10 = 10

Answer 2

`y=110x-540`

Explanation:

Point-slope form of a linear equation:
`y-y_1=m(x-x_1)`

(where
`m` is the slope and
`(x_1,y_1)` is a point on the line)

Given:

• 
  `\textsf{slope } (m) = 110`
• 
  `(x_1,y_1)=(5,10)`

Substitute these values into the equation:

`y-y_1=m(x-x_1)`

`y-10=110(x-5)`

`y-10=110x-550`

`y=110x-540`