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Solve 27=u^3 Plz hurry

User Robartsd
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Answer: Factoring: 27-u3

Theory : A difference of two perfect cubes, a3 - b3 can be factored into

(a-b) • (a2 +ab +b2)

Proof : (a-b)•(a2+ab+b2) =

a3+a2b+ab2-ba2-b2a-b3 =

a3+(a2b-ba2)+(ab2-b2a)-b3 =

a3+0+0-b3 =

a3-b3

Check : 27 is the cube of 3

Check : u3 is the cube of u1

Factorization is :

(3 - u) • (9 + 3u + u2)

Explanation:

User Rubund
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