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An apple drops from the roof of a skyscraper, which is 830 m tall.

Part A
Air resistance is zero. How many seconds will the apple take to reach the ground?
Express your answer in seconds.

Part B
Just before the apple hits the ground, how fast will the apple be moving?
Express your answer in meters per seconds

1 Answer

2 votes

Hi there!

We can use the following derivations of the kinematic equations Δd = vit + 1/2at² and vf² = vi² + 2ad to solve:

A)

t = √2h/g, let g = 9.8 m/s²

Plug in the given values:

t = √2(830)/9.8 ≈ 13.05 sec

B)

Use the equation vf = √2ad:

vf = √2(9.8)(830) ≈ 127.55 m/s

User Gabriel Ben Compte
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