Question

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Answer 1

3x^2+12=0

3x^2=0-12

3x^2=-12

X^2=12/3

x^2=4

X= root under4

x=2

Answer 2

Q3: x1=2+i, x2=2-i Q4: x1=-3/2+i, x2=-3/2-i

Explanation:

`x^(2) - 4x + 5 =0`

(
`4`±
`√(16 - 4*1*5)` ) /
`2` = (

x1= 2+i

x2= 2-i

`2x^(2) +6x + 5 =0`

(
`-6` ±
`√(36 - 4*2*5)` ) /
`4` = (-6 ±
`√(-4)` )/4= (-3 ± i)/2

x1 = -3/2 +i

x2 = -3/2 -i