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X^2=16^X
Find the value of x

1 Answer

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Answer:


{x}^(2) = {16}^(x) \\ \\ {x}^(2) = 2 {}^(4x)

introduce logarithm of base 10:


log( {x}^(2) ) = log( {2}^(4x) ) \\ \\ 2 log(x) = 4x log(2) \\ \\ log(x) = 0.6x \\ \\ x = 4 .{10}^(x)

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