Question

The minimum turning point

of a quadratic curve is (3,
-2).
Write an equation for this in
the form:
y=x²+ax+b

Answer 1

y = x² - 6x + 7

Explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the turning point and a is a multiplier

Here (h, k) = (3, - 2 ) and letting a = 1

y = (x - 3)² - 2 ← expand using FOIL

= x² - 6x + 9 - 2 ← collect like terms

= x² - 6x + 7