Question

Please help!
Part A and part B please

Answer 1

39

Explanation:

Given:

1st grade:

• 19%

2nd grade:

• 14%

3rd grade:

• 22%

4th grade:

• 26%

5th grade:

• 19%

TOTAL : 205 students.

To find -

Since the total students have been given, we just have to find the percentage of the 205 students that are 5th graders (19%).

So this can be found out:

19% of 205

Solution:

Always use this formula to find a percentage:

% / 100 = Part / Whole replace the given values:

19 / 100 = Part / 205

Cross multiply:

19 x 205 = 100 x Part, or

3895 = 100 x Part

Now, divide by 100 and get the answer:

Part = 3895 / 100 = 38.95

Since decimal cant be a whole number round to nearest tenth:

First note that 38.95 has two parts. The integer part to the left of the decimal point and the fractional part to the right of the decimal point:

• Integer Part: 38
• Fractional Part: 95

To round 38.95 to nearest tenth means to round the numbers so you only have one digit in the fractional part.

We use the following rules to round 38.95 to the nearest tenth:

• A) If the last digit in the fractional part of 38.95 is less than 5, then simply remove the last the digit of fractional part.
• B) If the last digit in the fractional part of 38.95 is 5 or more and the first digit in the fractional part is less than 9, then add 1 to the first digit of the fractional part and remove the second digit.
• C) If the last digit in the fractional part of 38.95 is 5 or more and the first digit in the fractional part is 9 then add 1 to the Integer part and make the fractional part 0.

With 38.95, rule C applies and the answer is:

39.0

Answer 2

39 students in 5th grade because 19% of 205 is 38.95