Answer:
1.) Cu(NO₃)₂ + 2 NaOH --> Cu(OH)₂ + 2 NaNO₃
2.) CuO + 2 HCl --> H₂O + CuCl₂
Step-by-step explanation:
Both of these reactions are substitution/double displacement reactions. The base reaction looks like this: AX + BY --> AY + BX. In other words, the negative ion of the first molecule bonds to the positive ion of the second molecule, and vice versa.
The products of the first equation are:
Cu(NO₃)₂ + NaOH --> Cu(OH)₂ + NaNO₃
The OH⁻ and the NO₃⁺ are polyatomic ions, meaning they stay together in these types of reactions. When determining the products, make sure to take note of the charges on the ions because subscripts may be necessary to balance them out.
Now you need to balance the coefficients. When balancing equations, begin with an element that is not present in more than one molecule on either side (ex. the oxygen is in two molecules on the reactant side). Keep in mind that the subscripts should be multiplied by the coefficients when determining the number of some elements.
The balanced first equation is:
Cu(NO₃)₂ + 2 NaOH --> Cu(OH)₂ + 2 NaNO₃
The process for the second equation is nearly identical to the first. The balanced second equation is:
CuO + 2 HCl --> H₂O + CuCl₂