Question

X^4+2x^2-48=0 what is the solution set

Answer 1

x. = sqrt 6 and x = - sqrt 6

Explanation:

x^4 + 2x^2-48=0

(x^2 - 6) (x^2 + 8) = 0

x^2 - 6 = 0

x = + sqrt 6 and x = - sqrt 6

x^2 + 8 = 0

x^2 = sqrt -8 (a negative number doesn’t have a real square root)